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Snowflake SnowPro Advanced: Data Scientist Certification Exam Sample Questions (Q115-Q120):
NEW QUESTION # 115
A pharmaceutical company is testing a new drug to lower blood pressure. They conduct a clinical trial with 200 patients. After treatment, the sample mean reduction in systolic blood pressure is 10 mmHg, with a sample standard deviation of 15 mmHg. You want to construct a 99% confidence interval for the true mean reduction in systolic blood pressure. Which of the following statements is most accurate concerning the appropriate distribution and critical value to use?
- A. Use a t-distribution with 199 degrees of freedom, and the critical value is slightly larger than 2.576.
- B. Use a z-distribution because we are estimating mean, and use a critical value of 1.96.
- C. Use a t-distribution with 200 degrees of freedom, and the critical value is close to 2.576.
- D. Use a chi-squared distribution with 199 degrees of freedom.
- E. Use a z-distribution because the sample size is large (n > 30), and the critical value is approximately 2.576.
Answer: A
Explanation:
The correct answer is B. While the sample size is considered 'large' (n > 30), it's more accurate to use a t-distribution when the population standard deviation is unknown and estimated by the sample standard deviation. The t-distribution accounts for the added uncertainty from estimating the standard deviation. The degrees of freedom are n-1 = 199. The critical value for a 99% confidence interval with a t-distribution and 199 degrees of freedom will be slightly larger than the z-score of 2.576. Option A is incorrect because using t-distribution is slightly better. Option C is incorrect because chi-squared distribution is for variance/standard deviation. Option D is incorrect since 1.96 is z score for 95%. Option E is incorrect as the degrees of freedom should be n-1.
NEW QUESTION # 116
A financial institution wants to predict fraudulent transactions on credit card data stored in Snowflake. The dataset includes features like transaction amount, merchant ID, location, time of day, and user profile information. The target variable is 'is_fraudulent' (0 or 1). You have trained several binary classification models (Logistic Regression, Random Forest, and Gradient Boosting) using scikit-learn and persisted them using a Snowflake external function for inference. To optimize for both performance (inference speed) and accuracy, which of the following steps should you consider before deploying your model for real-time scoring using the external function? SELECT ALL THAT APPLY.
- A. Increase the batch size of requests sent to the external function to amortize the overhead of invoking the external function itself, even if it increases latency for individual transactions.
- B. Evaluate the models on a representative held-out dataset within Snowflake using SQL queries (e.g., calculating AUC, precision, recall) to choose the model with the best balance of performance and accuracy before deploying it.
- C. Implement feature selection techniques (e.g., using feature importance scores from Random Forest or Gradient Boosting) to reduce the number of features passed to the external function, improving inference speed.
- D. Normalize or standardize the input features in Snowflake using SQL before passing them to the external function to ensure consistent scaling and potentially improve model performance.
- E. Replace the trained models with a simple rule-based system based solely on transaction amount. If the amount is greater than a threshold, flag it as fraudulent, as this will be faster than calling the external function.
Answer: B,C,D
Explanation:
A, C, and D are the correct answers. A addresses optimizing inference speed by reducing input complexity. C addresses ensuring data quality and model performance consistency. D covers rigorous model validation and selection. B could potentially improve throughput, but could also hurt latency, so it is not always an optimal choice without careful consideration of requirements. E is incorrect as its a huge oversimplification and will likely have low accuracy.
NEW QUESTION # 117
You are tasked with building a data science pipeline in Snowflake to predict customer churn. You have trained a scikit-learn model and want to deploy it using a Python UDTF for real-time predictions. The model expects a specific feature vector format. You've defined a UDTF named 'PREDICT CHURN' that loads the model and makes predictions. However, when you call the UDTF with data from a table, you encounter inconsistent prediction results across different rows, even when the input features seem identical. Which of the following are the most likely reasons for this behavior and how would you address them?
- A. The scikit-learn model was not properly serialized and deserialized within the UDTF. Ensure the model is saved using 'joblib' or 'pickle' with appropriate settings for cross-platform compatibility and loaded correctly within the UDTF's 'process' method. Verify serialization/deserialization by testing it independently from Snowflake first.
- B. The issue is related to the immutability of the Snowflake execution environment for UDTFs. To resolve this, cache the loaded model instance within the UDTF's constructor and reuse it for subsequent predictions. Using a global variable is also acceptable.
- C. The input feature data types in the table do not match the expected data types by the scikit-learn model. Cast the input columns to the correct data types (e.g., FLOAT, INT) before passing them to the UDTF. Use explicit casting functions like 'TO DOUBLE and INTEGER in your SQL query.
- D. There may be an error in model, where the 'predict method is producing different ouputs for the same inputs. Retraining the model will resolve the issue.
- E. The UDTF is not partitioning data correctly. Ensure the UDTF utilizes the 'PARTITION BY clause in your SQL query based on a relevant dimension (e.g., 'customer_id') to prevent state inconsistencies across partitions. This will isolate the impact of any statefulness within the function
Answer: A,C
Explanation:
Options A and C address the most common causes of inconsistent UDTF predictions with scikit-learn models. A covers the essential aspect of correct serialization/deserialization for model persistence and retrieval in the Snowflake environment, which ensures model state consistency. C focuses on the critical data type compatibility between the input data and the model expectations, which, if mismatched, can lead to unexpected prediction variations. Option B is incorrect, the model should be loaded in the process method. Option D is only relevant if you are using a stateful model, but it is still not the most likely cause. Option E is incorrect as the Model prediction method gives deterministic ouput for given inputs.
NEW QUESTION # 118
A marketing analyst is building a propensity model to predict customer response to a new product launch. The dataset contains a 'City' column with a large number of unique city names. Applying one-hot encoding to this feature would result in a very high-dimensional dataset, potentially leading to the curse of dimensionality. To mitigate this, the analyst decides to combine Label Encoding followed by binarization techniques. Which of the following statements are TRUE regarding the benefits and challenges of this combined approach in Snowflake compared to simply label encoding?
- A. Binarizing a label encoded column using a simple threshold (e.g., creating a 'high_city_id' flag) addresses the curse of dimensionality by reducing the number of features to one, but it loses significant information about the individual cities.
- B. Label encoding followed by binarization will reduce the memory required to store the 'City' feature compared to one-hot encoding, and Snowflake's columnar storage optimizes storage for integer data types used in label encoding.
- C. While label encoding itself adds an ordinal relationship, applying binarization techniques like binary encoding (converting the label to binary representation and splitting into multiple columns) after label encoding will remove the arbitrary ordinal relationship.
- D. Binarization following label encoding may enhance model performance if a specific split based on a defined threshold is meaningful for the target variable (e.g., distinguishing between cities above/below a certain average income level related to marketing success).
- E. Label encoding introduces an arbitrary ordinal relationship between the cities, which may not be appropriate. Binarization alone cannot remove this artifact.
Answer: A,B,D,E
Explanation:
Option A is true because label encoding converts strings into integers, which are more memory-efficient than storing numerous one-hot encoded columns. Snowflake's columnar storage further optimizes integer storage. Option B is also true; label encoding inherently creates an ordinal relationship that might not be valid for nominal features like city names. Option C is incorrect; simple binarization (e.g., > threshold) of label encoded data doesn't remove the arbitrary ordinal relationship; more complex binarization techniques would be needed. Option D is accurate; binarization reduces dimensionality but sacrifices granularity, leading to information loss. Option E is correct because carefully chosen thresholds might correlate with the target variable and improve predictive power.
NEW QUESTION # 119
A data scientist is preparing customer churn data for a machine learning model in Snowflake. The dataset contains a 'Contract_Type' column with values 'Month-to-Month', 'One Year', and 'Two Year'. They want to use label encoding to transform this categorical feature into numerical values. Which of the following SQL statements correctly implements label encoding for the 'Contract_Type' column, assigning 'Month-to-Month' to 0, 'One Year' to 1, and 'Two Year' to 2, and creates a new column named 'Contract_Type_Encoded'? Additionally, the data scientist wants to handle potential NULL values in 'Contract_Type' by assigning them the value of -1.
- A. Option D
- B. Option B
- C. Option A
- D. Option E
- E. Option C
Answer: D
Explanation:
Both options B and D achieve the desired label encoding and handle NULL values correctly. Option B creates a new table based on the transformed dataset, which is a common approach for preserving the original data. Option D directly updates the existing table which could be appropriate depending on the team and security structure.
NEW QUESTION # 120
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